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Old 11-05-2007, 02:48 PM  
player > class <--- aLWAYs
 
Character: CyberSteel
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Default class/player) vs. (player/class) = to A

can u answer this w/who r u ? and y do u play EQ2

I'm CyberSteel, i'm looking for people like myself who like to have fun and thrive at what they do
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Old 11-05-2007, 02:51 PM  
Original Gangster
 
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Default Re: class/player) vs. (player/class) = to A

I am Xenobe. I shit on your life.
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Old 11-05-2007, 03:05 PM  
shaken blueberry white tea.
 
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Default Re: class/player) vs. (player/class) = to A

now in english?
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Old 11-05-2007, 03:17 PM  
Yo Soy La Pequeña Prohibida
 
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Default Re: class/player) vs. (player/class) = to A

Quote:
Originally Posted by Trumak View Post
I am Xenobe. I shit on your life.
Fact
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Old 11-05-2007, 03:31 PM  
player > class <--- aLWAYs
 
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Default Re: class/player) vs. (player/class) = to A

Quote:
Originally Posted by Sylvia View Post
now in english?
ok in any given content in EQ2, does it matter more what and how many class u have to play or players that can play a well class ?

Last edited by CyberSteel; 11-05-2007 at 03:33 PM.
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Old 11-05-2007, 03:39 PM  
Hillbilly Deluxe
 
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Default Re: class/player) vs. (player/class) = to A

Quote:
Originally Posted by CyberSteel View Post
ok in any given content in EQ2, does it matter more what and how many class u have to play or players that can play a well class ?
LFG, i thought you had spam filters running. This one got past the bot farmer filter.
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Old 11-05-2007, 03:42 PM  
Retired?
 
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Default Re: class/player) vs. (player/class) = to A

I hear he's NPU's new Paladin app!
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Old 11-05-2007, 03:51 PM  
shaken blueberry white tea.
 
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Default Re: class/player) vs. (player/class) = to A

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Originally Posted by CyberSteel View Post
ok in any given content in EQ2, does it matter more what and how many class u have to play or players that can play a well class ?
Que?
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Old 11-05-2007, 04:09 PM  
Ten Ton Hammer
 

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Default Re: class/player) vs. (player/class) = to A

I don't get it.
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Old 11-05-2007, 04:11 PM  
Pokerape go!
 
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Default Re: class/player) vs. (player/class) = to A

If A = B and B = C we can only assume A = C
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